05 FE450

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Joined
Jul 10, 2007
Messages
3
Location
Prescott, Arizona
Hi I'm a newbie here. Local shop has a 05 FE450. I was wondering what the tranny is simlar to KTM XC-W or XC. Thanks, TripleW
 
TripleW said:
Hi I'm a newbie here. Local shop has a 05 FE450. I was wondering what the tranny is simlar to KTM XC-W or XC. Thanks, TripleW

Similar to a xc-w. Both have six speeds that are a bit more wide ratio than the xc close ratio gears.
 
Husaberg trans

primary ratio: 29:78= 2.68:1

1st grear 14:33=2.35:1
2cnd gear 17:30=1.76:1---25% change
3rd gear 19:26=1.36:1--22.5% change
4th gear 23:25=1.08:1--20.5% change
5th gear 24:22=.91:1--15.5% change
6th gear 27:20=.74:1--18.5% change

final 14:48=3.42:1

KTM trans.

primary ratio 33:76=2.30:1 same on both xc-xcw-exc

XC
1ST 14:34=2.42:1
2CND 17:31=1.82:1 --24.7% change
3RD 20:28=1.4:1---23% change
4TH 22:26=1.18:1--15.5% change
5TH 24:24=1.00:1--15% change
6TH 21:18=.857:1--15% change

XCW/EXC
1st 14:34=2.42:1
2cnd 17:31=1.82:1--24.7% change
3rd 19:28=1.47:1--19% change
4th 22:26=1.18:1--19.5% change
5th 24:23=.958:1--18.8% change
6th 26:21=.807:1--15.7% change

FINAL:
XC/XCW 14:50=3.57:1 EXC 15:45=3.0:1 (STREET LEGAL GEARING)
 
so in that case the difference between 1st and 6th in both bikes is absolutely identical.

2.35 minus .74 = 1.61

and

2.42 - .81 = 1.61

in the meantime he can swop 6th on the husey to make the box even closer in ratio.

regards

Taffy
 
So Taffy,

Given the primary ratio of the HBG of 2.68:1 and an RPM of 8000 the main shaft speed of the HBG would be 2985 RPM, and then given the .74:1 ratio of sixth gear the counter shaft would be at 3761 RPM. With the final reduction ratio of 3.42:1 the rear wheel RPM should be 1099. So, if we take the rear wheel diameter of say 22" (this includes the rim diameter plus the side wall height of the Pirrelli MT 18 120/100 tire I run) X 3.141=69.1 inches per revolution or circumference, X 1099 RPM =75943 iches per min / 12 to = 6328.59 feet per min / 5280' in a mile =1.19 miles per minute X 60 mins = 71.91mph @ 8000 rpm.

The KTM has a primary reduction ratio of 2.30:1, and at 8000 RPM the main shaft would be at 3478 RPM. With the sixth gear ratio of .80:1, the counter shaft RPM would be 4173. The final drive reduction ratio of 3.57:1 the rear wheel would be at 1168 RPM. 69.1X1168=80708.8ipm/12=6725.7fpm/5280"=1.27X60=76.43mph.

This is a difference of 6.3%

Did I get that right? .
 
DaleEO said:
So Taffy,

Given the primary ratio of the HBG of 2.68:1 and an RPM of 8000 the main shaft speed of the HBG would be 2985 RPM, and then given the .74:1 ratio of sixth gear the counter shaft would be at 3761 RPM. With the final reduction ratio of 3.42:1 the rear wheel RPM should be 1099. So, if we take the rear wheel diameter of say 22" (this includes the rim diameter plus the side wall height of the 120/100 tire I run) X 3.141=69.1 inches per revolution or circumference, X 1099 RPM =75943 iches per min / 12 to = 6328.59 feet per min / 5280' in a mile =1.19 miles per minute X 60 mins = 71.91mph @ 8000 rpm.

The KTM has a primary reduction ratio of 2.30:1, and at 8000 RPM the main shaft would be at 3478 RPM. With the sixth gear ratio of .80:1, the counter shaft RPM would be 4173. The final drive reduction ratio of 3.57:1 the rear wheel would be at 1168 RPM. 69.1X1168=80708.8ipm/12=6725.7fpm/5280"=1.27X60=76.43mph.

This is a difference of 6.3%

Did I get that right? .

Show Off.... :p
 
Wow! Thanks for the info. So the FE450E is a short stroke motor with a wide ratio gearbox. Right?

Hey , Another Question. Can a 450 be made into a 550 or are the engine cases specific to the bore size?

Thanks for the response guys I appreciate it. TripleW
 
all that matters is the difference between first and sixth gear and they are identical. everything else can be adjusted using new front and rear sprockets. it doesn't matter a bean that the primary ratios are different etc.

if you're gonna get me on the rolling circumference of pjung yang ming rear tyre compared to a michelin well - you win!

triple
are you gonna buy this bike or not becasue you're talking like dave knight?

regards

Taffy
 
Taffy said:
all that matters is the difference between first and sixth gear and they are identical. everything else can be adjusted using new front and rear sprockets. it doesn't matter a bean that the primary ratios are different etc.

True, except for the fact that the overall gear ratio spreads of the KTM XC/W(EXC) and the Berg are not quite the same. The Berg has a slightly wider 3.18 overall ratio spread compared to a 3.00 ratio spread for the KTM. The main difference being in a wider 5th to 6th gear gap in the Berg tranny.
 
DaleEO said:
Husaberg trans

primary ratio: 29:78= 2.68:1

1st grear 14:33=2.35:1
2cnd gear 17:30=1.76:1---25% change
3rd gear 19:26=1.36:1--22.5% change
4th gear 23:25=1.08:1--20.5% change
5th gear 24:22=.91:1--15.5% change
6th gear 27:20=.74:1--18.5% change

final 14:48=3.42:1

KTM trans.

primary ratio 33:76=2.30:1 same on both xc-xcw-exc

XC
1ST 14:34=2.42:1
2CND 17:31=1.82:1 --24.7% change
3RD 20:28=1.4:1---23% change
4TH 22:26=1.18:1--15.5% change
5TH 24:24=1.00:1--15% change
6TH 21:18=.857:1--15% change

XCW/EXC
1st 14:34=2.42:1
2cnd 17:31=1.82:1--24.7% change
3rd 19:28=1.47:1--19% change
4th 22:26=1.18:1--19.5% change
5th 24:23=.958:1--18.8% change
6th 26:21=.807:1--15.7% change

FINAL:
XC/XCW 14:50=3.57:1 EXC 15:45=3.0:1 (STREET LEGAL GEARING)

Now, if we look at the primary drive difference between the KTM and HBG, the HBG has a 14% lower primary drive ratio than the KTM. The KTM has a first gear ratio 3 % lower than the HBG, so 14%-3%=11% lower counter shaft speed for a given RPM on the Berg, or 11% more mechanical advantage in first. But either way the primary drive ratio is 14% lower than the KTM, but is only 6.3% slower @ a given RPM in 6th gear.

So, just to finish off fun with math here, on a recent outing my speedo max speed capture read 102 mph after a run across a dry lake. I wanted to figure out how many revs the motor was turning:

11,500 RPM divided by the primary ratio of 2.68=4291 main shaft RPM. Take 4291 and add 26% which is the amount of overdrive (.74) and that equals a counter shaft speed of 5406 RPM. Take the counter shaft speed of 5406 RPM and divide that by my final drive ratio of 3.46 (15/52) and you get a rear wheel speed of 1562 RPM times the circumference of 69 inches and you get 10,782 inches per minute. Divide 10,782 by 12 to get 8985 feet per min. Divide that by the distance of a mile 5,280 and you get 1.70 miles per minute times 60 minutes and you get 102 miles per hour.
 

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